# Line slope calculator 4x+y=42

**Straight line given by points A[8; 10] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = -4x+42

**Canonical form of the line equation:**4x+y-42 = 0

**Parametric form of the line equation:**

x = t+8

y = -4t+10 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 10.5

**Y intercept:**y

_{0}= q = 42

**Distance line from the origin:**d

_{0}= 10.1865

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[8.5; 8]

**Perpendicular Bisector equation:**x-4y+23.5 = 0

**Vector OA = (8; 10) ; |OA| = 12.8062**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 132**

**Angle ∠ AOB = 17°39' = 0.3081 rad**